`dy/dx`= `-2/(2x+3)^2`

dy/dx = (x-7)(2x-9)

dy/dx = (x-y+3)/(2x-2y+5)

Solve: dy/dx=(2)/(x+2y-3)

dy/dx = cos^2x

dy/dx - y/x = 2x^2

dy/dx=(x-y+1)/(2x-2y+3)

If =(sqrt(a^2+x^2)+sqrt(a^2-x^2))/(sqrt(a^2+x^2)-sqrt(a^2-x^2)) , show that (dy)/(dx)=(2a^2)/(x^3){1+(a^2)/(sqrt(a^4-x^4))} .

dy/dx(2x^2+1)^2

(x-1) dy/dx = 2x^3y

y^2+x^2(dy)/(dx)=x y(dy)/(dx)