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If is the angle between any two vectors ` -> a` and ` -> b` , then `| -> adot -> b|=| -> axx -> b|` when `theta` is equal to (a) 0 (B) `pi/4` (C) `pi/2` (d) `pi`

A

0

B

`pi/4`

C

`pi/2`

D

`pi`

Text Solution

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The correct Answer is:
B
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