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The value of lamda for which the vectors...

The value of `lamda` for which the vectors `3hat(i)-6hat(j)+hat(k)` and `2hat(i)-4hat(j)+lamda hat(k)` are parallel is

A

`2/3`

B

`3/2`

C

`5/2`

D

`2/5`

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To find the value of \(\lambda\) for which the vectors \( \vec{A} = 3\hat{i} - 6\hat{j} + \hat{k} \) and \( \vec{B} = 2\hat{i} - 4\hat{j} + \lambda \hat{k} \) are parallel, we can use the property that two vectors are parallel if the ratios of their corresponding components are equal. ### Step-by-Step Solution: 1. **Identify the components of the vectors:** - For vector \( \vec{A} \): - \( x_1 = 3 \) - \( y_1 = -6 \) - \( z_1 = 1 \) - For vector \( \vec{B} \): - \( x_2 = 2 \) - \( y_2 = -4 \) - \( z_2 = \lambda \) 2. **Set up the ratios for parallel vectors:** Since the vectors are parallel, we can set up the following equations based on the ratios of their components: \[ \frac{x_1}{x_2} = \frac{y_1}{y_2} = \frac{z_1}{z_2} \] This gives us: \[ \frac{3}{2} = \frac{-6}{-4} = \frac{1}{\lambda} \] 3. **Simplify the ratios:** - The second ratio simplifies to: \[ \frac{-6}{-4} = \frac{6}{4} = \frac{3}{2} \] Thus, we have: \[ \frac{3}{2} = \frac{3}{2} \] This confirms that the first two ratios are equal. 4. **Solve for \(\lambda\):** Now, we can use the first and the third ratio: \[ \frac{3}{2} = \frac{1}{\lambda} \] Cross-multiplying gives: \[ 3\lambda = 2 \] Dividing both sides by 3: \[ \lambda = \frac{2}{3} \] 5. **Conclusion:** The value of \(\lambda\) for which the vectors are parallel is: \[ \lambda = \frac{2}{3} \]
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