Home
Class 12
MATHS
Assertion (A) : The direction of cosines...

Assertion (A) : The direction of cosines of vector `vec(A)=2hat(i)+4hat(j)-5hat(k)` are `(2)/(sqrt(45)),(4)/(sqrt(45)),-(5)/(sqrt(45))`.
Reason (R ) : A avector having zero magnitude and artitrary direction is called 'zero vector' or 'null vector'.

A

Both A and R are true and R is NOT the correct explanation of A

B

Both A and R are true but R is NOT the correct explanation of A

C

A is true but R is false

D

A is false but R is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we need to evaluate the assertion (A) and reason (R) provided. Let's break it down step by step. ### Step 1: Find the Direction Cosines of the Vector Given the vector \( \vec{A} = 2\hat{i} + 4\hat{j} - 5\hat{k} \). The direction cosines of a vector are given by the formulas: \[ l = \frac{a}{\sqrt{a^2 + b^2 + c^2}}, \quad m = \frac{b}{\sqrt{a^2 + b^2 + c^2}}, \quad n = \frac{c}{\sqrt{a^2 + b^2 + c^2}} \] where \( a, b, c \) are the components of the vector along the \( \hat{i}, \hat{j}, \hat{k} \) directions respectively. ### Step 2: Calculate the Magnitude of the Vector First, we need to find the magnitude of the vector \( \vec{A} \): \[ |\vec{A}| = \sqrt{a^2 + b^2 + c^2} = \sqrt{2^2 + 4^2 + (-5)^2} \] Calculating each term: \[ 2^2 = 4, \quad 4^2 = 16, \quad (-5)^2 = 25 \] Adding these values: \[ |\vec{A}| = \sqrt{4 + 16 + 25} = \sqrt{45} \] ### Step 3: Calculate the Direction Cosines Now we can find the direction cosines: \[ l = \frac{2}{\sqrt{45}}, \quad m = \frac{4}{\sqrt{45}}, \quad n = \frac{-5}{\sqrt{45}} \] Thus, the direction cosines of the vector \( \vec{A} \) are: \[ \left( \frac{2}{\sqrt{45}}, \frac{4}{\sqrt{45}}, -\frac{5}{\sqrt{45}} \right) \] ### Step 4: Verify Assertion (A) The assertion states that the direction cosines of the vector \( \vec{A} \) are: \[ \left( \frac{2}{\sqrt{45}}, \frac{4}{\sqrt{45}}, -\frac{5}{\sqrt{45}} \right) \] Since we calculated the direction cosines and they match the assertion, we conclude that assertion (A) is true. ### Step 5: Evaluate Reason (R) The reason states that a vector having zero magnitude and arbitrary direction is called a 'zero vector' or 'null vector'. To verify this, we note that the magnitude of a vector \( \vec{A} \) is zero if all its components are zero: \[ |\vec{A}| = \sqrt{a^2 + b^2 + c^2} = 0 \implies a = 0, b = 0, c = 0 \] Thus, the reason (R) is also true. ### Conclusion Both the assertion (A) and reason (R) are true. However, reason (R) does not explain assertion (A) since they are discussing different properties of vectors. ### Final Answer - Assertion (A) is true. - Reason (R) is true. - Reason (R) is not the correct explanation of assertion (A). ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The direction cosines of a vector hat(i) + hat(j) + sqrt(2)hat(k) are :

What are the direction cosines of the vector (2hat(i)+ hat(j) -2hat(k)) ?

Writhe the direction cosines of the vectors -2hat i+hat j-5hat k

Write the direction cosines of the vector vec r=6hat i-2hat j+3hat k

Write the direction cosines of the vector -2hat i+hat j-5hat k

Find a unit vector in the direction of vector vec(A)=(hat(i)-2hat(j)+hat(k)) .

Find the unit vector in the direction of the vector : vec(b)=2hat(i)+hat(j)+2hat(k)

Find the unit vector in the direction of the vector : vec(a)=2hat(i)-3hat(j)+hat(k) .

Find the unit vector in the direction of the vector : vec(a)=2hat(i)+3hat(j)+hat(k)

Find the unit vector in the direction of the vector : vec(a)=2hat(i)-3hat(j)+6hat(k)