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A galvanometer of 100 Omega resistance g...

A galvanometer of `100 Omega` resistance gives full scale deflection when 10 mA of current is passed. To convert it into 10 A range ammeter, the resistance of the shunt required will be

A

`10 Omega`

B

`0.10 Omega`

C

`0.01 Omega`

D

`0.001 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`S = (i_(g)G)/(i - i_(g))=(100xx0.01)/(10-0.01)=0.1Omega`
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