Home
Class 11
CHEMISTRY
KMnO(4) reacts with ferrous ammonium sul...

`KMnO_(4)` reacts with ferrous ammonium sulphate according to the equation `MnO_(4)^(-)+5Fe^(2+)+8H^(+) rarr Mn^(2+)+5Fe^(3+)+4H_(2)O`, here `10 ml` of `0.1 M KMnO_(4)` is equivalent to

Promotional Banner

Similar Questions

Explore conceptually related problems

KMnO_(4) react with oxalic acid according to the equation, 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+ 10 CO_(2)+8H_(2)O , here 20 ml of 0.1 M KMnO_(4) is equivalemt to

KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10CO_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

KMnO_(4) reacts with oxalic acid according to the equation 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10Co_(2)+8H_(2)O Here, 20mL of 1.0M KMnO_(4) is equivalent to:

KMnO_(4) reacts with oxalic acid according to the equation: 2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to2Mn^(2+)+10CO_(2)+8H_(2)O 20mL of 0.1M KMnO_(4) will react with:

KMnO_4 reacts with oxalic acid according to the equation 2MnO_4 + 5C_2 O_4^(2-) + 16H^+ rarr 2Mn^(2+) + 10CO_2 + 8H_2O Here, 20mL of 0.1M KHMnO_4 is equivalent to :

KMnO_4 reacts with oxalic acid according to the equation 2MnO_4 + 5C_2 O_4^(2-) + 16H^+ rarr 2Mn^(2+) + 10CO_2 + 8H_2O Here, 20mL of 0.1M KHMnO_4 is equivalent to :

Balance the equation MnO_4^- +H^+ +Fe^2 rarr Mn^2 + H_2O + Fe^3^+