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A student very cautiously traces the pat...

A student very cautiously traces the path of a ray through a glass slab for different values of the angle of incidence `(/_i)`. He then measures the corresponding values of the angle of refraction `(/_r)` and the angle of emergence `(/_e)` for every value of the angle of incidence. On analysing these measurements of angles, his conclusion would be

A

`angle`i gt `angle`r gt `angle`e

B

`angle`i lt `angle`r lt `angle`e

C

`angle`i = `angle`e gt `angle`r

D

`angle`i = `angle`e lt `angle`r

Text Solution

Verified by Experts

The correct Answer is:
B

{Angle of incidence) `angle`i = `angle`e (angle of emergence) because the direction of incident ray and emergent ray is parallel to each other.
`angle`e >`angle`r (angle of refraction) because at point of emergence light is entering into opticaily rarer medium (air) from optically denser medium (glass), so light will bend away from the normal making the angle bigger.
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