`int(4x+3)/(2x+1)dx`

int(4x)/(2x^2+x-1)dx=

Evaluate: int(3x)/(1+2x^4)dx

(i) int (3x^2)/(x^6+1) dx (ii) int (3x)/(1+2x^4) dx

int(4x+1)/(2x^(2)+x+1)dx

int(4x^3+3x)/(x^4+1)dx=?

int(3x)/(1+2x^(4))dx

" (5) "int(x^3)/(1+2x^(4))dx

(i) int_0^4 (2x+3) dx (ii) int_0^4 (2x-1)dx

int(x^4-3)/(x^2+2x+1)dx

Integrate the following (1) intx^(-3/2)dx (2) intsin60^(@)dx (3) int(1)/(10x)dx (4) int(2x^(3)-x^(2)+1)dx