`int_0^3sqrt(4-y)dy`

int sqrt(4-y^(2))dy

int_0^2 int_0^sqrt(4+x^2) (dx dy)/(4+x^2+y^2) =

int_0^4sqrt(3x+4)dx=?

int_0^4 sqrt(1-4x)dx

Evaluate: int_0^2 sqrt(4-x^2) dx

int_0^1y^2sqrt(1-y^2)dy

int_0^1 int_0^sqrt(1+x^2) (dy dx)/(1+x^2+y^2)

Area bounded by the curves y^2=4x and y=2x is equal to (A) int_0^1(2sqrt(x)-2x)dx (B) 1/3 (C) 2/3 (D) int_0^2(y/2-y^2/4)dy

f(x)=sqrt(x)-(1)/(3)int_(0)^(x)sqrt(xy)f(y)backslash dy,AA x in R,x>=0 then f(1)=