The orbital angular momentum of an electron is 2s orbital is

Options

A. `+1/2 cdot h/(2pi)`
B. zero
C. `h/(2pi)`
D. `sqrt2 cdot h/(2pi)`

Answer

To find the orbital angular momentum of an electron in the 2s orbital, we can follow these steps:

### Step 1: Identify the Orbital
The question specifies the 2s orbital. The "s" indicates that this is an s-type orbital.

### Step 2: Determine the Azimuthal Quantum Number (L)
The azimuthal quantum number (L) is associated with the shape of the orbital:
- For s orbitals, L = 0
- For p orbitals, L = 1
- For d orbitals, L = 2
- For f orbitals, L = 3

Since we are dealing with the 2s orbital, we have:
- L = 0

### Step 3: Use the Formula for Orbital Angular Momentum
The formula for the orbital angular momentum (L) is given by:
\[ L = \sqrt{L(L + 1)} \cdot \frac{h}{2\pi} \]
Where:
- \( h \) is Planck's constant.

### Step 4: Substitute the Value of L into the Formula
Now, substituting L = 0 into the formula:
\[ L = \sqrt{0(0 + 1)} \cdot \frac{h}{2\pi} \]
\[ L = \sqrt{0} \cdot \frac{h}{2\pi} \]
\[ L = 0 \cdot \frac{h}{2\pi} \]
\[ L = 0 \]

### Step 5: Conclusion
Thus, the orbital angular momentum of an electron in the 2s orbital is:
\[ \text{Orbital Angular Momentum} = 0 \]

### Final Answer
The orbital angular momentum of an electron in the 2s orbital is **0**.

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