Tertiary amine is obtained in the reaction

Options

A. Aniline `overset (CH_3l) rarr overset (CH_3l) rarr`
B. Aniline `overset (CH_3l) rarr`
C. Nitrobezene`overset (Sn//HCl) rarr`
D. None of these

Answer

To obtain a tertiary amine from aniline, we can follow a step-by-step reaction process. Here’s how it works:

### Step-by-Step Solution:

1. **Identify the Starting Material**:
- The starting material is aniline (C6H5NH2), which has an amino group (-NH2) attached to a benzene ring.

2. **React Aniline with Methyl Iodide (CH3I)**:
- We will react aniline with methyl iodide (CH3I). Since we need to form a tertiary amine, we will use two moles of CH3I in this reaction.

3. **First Reaction**:
- In the first step, one mole of CH3I reacts with aniline. The nitrogen atom in aniline has a lone pair of electrons that can attack the carbon atom in CH3I, resulting in the formation of a methylated product.
- The reaction can be represented as:
\[ \text{C6H5NH2} + \text{CH3I} \rightarrow \text{C6H5NHCH3} + \text{HI} \]
- Here, one hydrogen atom from the amino group is replaced by a methyl group, forming a secondary amine (C6H5NHCH3).

4. **Second Reaction**:
- Now, we take the secondary amine (C6H5NHCH3) and react it with another mole of CH3I.
- The reaction can be represented as:
\[ \text{C6H5NHCH3} + \text{CH3I} \rightarrow \text{C6H5N(CH3)2} + \text{HI} \]
- In this step, another hydrogen atom from the nitrogen is replaced by another methyl group, resulting in the formation of a tertiary amine (C6H5N(CH3)2).

5. **Final Product**:
- The final product is a tertiary amine, specifically dimethyl aniline (C6H5N(CH3)2).

### Conclusion:
- The reaction of aniline with two moles of methyl iodide leads to the formation of a tertiary amine.