If `x^(2) + y^(2)=6xy`, prove that 2 log `(x+ y)= log x + log y + 3 log 2`

If x^2 + y^2 = 6xy , prove that 2 log (x + y) = logx + logy + 3 log 2

If x^2 + y^2 = 10xy , prove that 2 log (x + y) = log x + log y + 2 log 2 + log 3 .

If x^2+y^2=6xy, prove that 2log(x+y)=logx+logy+3log2

If x^2+y^2=7xy, then prove that log((x+y)/(3))=1/2(logx+logy).

If x^2+y^2=25xy. then prove that 2log(x+y)=3log3+logx+logy.

Prove that log_(a)xy=log_(a)x+log_(a)y.

If x^2+y^2=7xy then show that 2log(x+y)=logx+logy+2log3.

We can write log"" x/y = log (x.y^(-1 )) Can you prove that log"" x/y = log x - logy using product and power rules.

If x^2+y^2=27xy , then show that log((x-y)/(5))=1/2[logx+logy] .

If x ^( log y) = log x, then prove that (dy)/(dx) = (y)/(x) ((1- log x log y)/( (log x) ^(2)))