`6 xx 10^(20)` molecules of `CO_(2)` are removed from 220 milligram of `CO_(2).` What are the remaining moles of `CO_(2)`?

Options

A. `4 xx 10 ^(-3)` mole
B. `5 xx 10 ^(-3) ` mole
C. `2 xx 10 ^(-3) ` mole
D. `6 x 10 ^(-3)` mole

Answer

A

Explanation

Initial moles of
`CO _(2) = (220 xx 10 ^(-3))/( 44) = 5 xx 10 ^(-3) ` mol
Removed moles of
`CO _(2) = ( 6 xx 10 ^(20))/( 6 xx 10 ^(23)) = 1 xx 10 ^(-3) ` mol
Remaining moles of
`CO _(2) = 4 xx 10 ^(-3) ` mol