`K_(c )` for the reaction
`(1)/(2) N_(2(g)) + (1)/(2) O_(2(g)) + (1)/(2) Br_(2 (g)) ` will `rarr NONr_((g))` be ?
Given :
`2 NO_((g)) rarr N_(2(g)) + O_(2(g)), k = 10^(30)`
`NO_((g)) + (1)/(2) Br_(2(g)) rarr NOBr_((g)) , k_(2)= 10^(15)`

Options

A. `10^(+45)`
B. `10^(+15)`
C. `10^(-15)`
D. 1

Answer

D

Explanation

`(1)/(2) N_(2(g)) + (1)/(2) O_(2(g)) + (1)/(2) Br_((g)) rarr NOBr_((g)) ……. K`
`2 NO_((g)) rarr N_(2(g)) + O_(2(g)) cdots K_(1) = 10^(30)`
`NO_((g)) + (1)/(2) Br_(2(g)) rarr NOBr cdots K_(2) =10^(15)`
`K = (K^(2))/(sqrt(K_(1))) =1 `