0. 01 mol NaOH is added to 10 litres of water. The pH of the solution is _____

Answer

11

Explanation

[OH] `= (0.1)/(10) = 10^(-3)` M
`[ H^(+)] = (K_(w))/([OH^(-)]) = (10^(-14))/(10^(-3))= 10^(-11) M`
`:. pH = - "log"_(10) [ H^(+)] = -"log"_(10) (10^(-11)) = 11`