100 mL of 1 M acetic acid is shaken with 4 g of charcoal. The concentration of acetic acid after adsorption is 0. 6 M. Calculate the mass in grams of acetic acid adsorbed per gram of charcoal. [Molar mass of acetic acid is 60g/ mol.]

Answer

`0.60`

Explanation

Initial moles of acetic acid
`= (1 xx 10 )/( 100) = 0.1 ` mol
Moles after adsorption
` = ( 0.6 xx 100)/(1000) = 0. 06` mol
Moles adsorbed
`=0.1 - 0.06 = 0.04` mol
Mass adsorbed `= 0.04 xx 60 = 2. 4 g`
Mass adsorbed per gram of charcoal
`= (2. 4)/(4) = 0. 60 g`