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Consider the following reaction : Cu O...

Consider the following reaction :
`Cu O (s) + H _(2) (g) hArr Cu (s)`
`+ H _(2) O (g) , K _(1) = 2 xx 10 ^(15)`
`H _(2) (g) + (1)/(2) O _(2) (g) hArr H _(2) O (g), K _(2) = 5 xx 10 ^(22)`
The equilibrium constant for the reaction :
`CuO (s) hArr Cu s + (1)/(2) O _(2) (g)` would be :

A

`1 xx 10 ^(38)`

B

`4 xx 10 ^(-8)`

C

`K _(1) + K _(2)`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
The equilibrium constant for the reaction
`CuO (s) hArr Cu (s) + 0.5 O _(2) (g) ` would be -
` ( k _(1))/( k_(2)) = ( 2 xx 10 ^(15))/( 5 xx 10 ^(22)) = 4 xx 10 ^(-8)`
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