Assuming that the mass of an electron is `9 xx 10 ^(-31)` kg, and the value of Planck's constant is `6. 62 xx 10^(-34 )`Js, calculate the wavelength (in angstrom) of the electron travelling with a speed of `2.65 xx 10 ^(6) m//s` ?

Answer

`2.78`

Explanation

`lamda = (h)/(mv) = ( 6.62 xx 10 ^(-34))/( 9 xx 10 ^(-31) xx 2. 65 xx 10 ^(6))`
`= 2. 78 xx 10 ^(-10) m = 2 78 //A A `