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A nucleus ruptures into two nuclear part...

A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to `2 : 1`. What will be the ratio of their nuclear size (nuclear radius)?

A

`2 ^(1//3) :1`

B

`1 : 2 ^( 1//3)`

C

`3 ^( 1//3 ) :1 `

D

`1 : 3 ^( 1//3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`m _(1) 2 v = m _(2) v `
` ( m _(1))/( m _(2)) = (1)/(2)`
`(( 4)/(3) pi r _(1) ^(3) rho )/( (4)/(3) pi r _(2) ^(3) rho ) = (1)/(2)`
`(r _(1))/(r _(2)) = ( 1)/( 2 ^( 1//3))`
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Knowledge Check

  • A nucleus splits into two nuclear parts which have their velocity ratio equal to 5 : 1 . What will be the ratio of their nuclear radius ?

    A
    `5^(1//3) : 1`
    B
    `1 : 5^(1//3)`
    C
    `3^(1//2) : 1`
    D
    `1 : 3^(1//2)`

  • A nucleus desintegrated into two nucleus which have their velocities in the ratio of 2 : 1 . The ratio of their nuiclear sizes will be

    A
    `3^(1/2) : 1`
    B
    `1 : 2^(1//3)`
    C
    `2^(1//3): 1`
    D
    `1 : 3^(1/2)`

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