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Treat the bulb as a point source of electromagnetic radiation, estimate the maximum magnitudes of the electric and magnetic fields of the light that is incident on this page because of the visible light coming from your desk lamp. Assume only 5% light is efficient in converting electrical energy to visible light. (HINT: assume 60W bulb and a distance of 0.3 m)

A

`45 V//m, 1.5 xx 10^(-7)T`

B

`4.6 V//m, 1.5 xx10^7T`

C

`0.35 V//m, 1.5 xx 10^(-7)T`

D

`0.045 V//m, 1.5 xx 10^(-2)T`

Text Solution

Verified by Experts

The correct Answer is:
A

`I=P/(4pir^2),` where `P=5%` of 60W
&
`I = 1/2epsilon_0E_0^2 xxc`
`=1/(2mu_0)B_0^2xxc`
`implies E_0 = sqrt((2I)/(epsilon_0c))`
& `B_0 = sqrt((2mu_0I)/c)`
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