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In the given circuit the average power d...

In the given circuit the average power developed is:

A

`50sqrt(2)` watt

B

200 watt

C

`150sqrt(2)` watt

D

`200sqrt(2)` watt

Text Solution

Verified by Experts

The correct Answer is:
B
Impedance of the circuit is given by
`Z=sqrt(R^(2)+X_(L)^(2)) = sqrt(R^(2)+(omegaL)^(2))`
`Z= sqrt((50)^(2) + (0.2 xx 250)^(2))`
`Z= sqrt(2500 +(50)^(2)) =50sqrt(2)`
Average power is given by
`:.P= V_("rms") I_("rms") cos phi`
`P= (V_("rms")^(2))/(Z^(2))R`
`P=(((200)/(sqrt(2)))^(2))/((50sqrt(2))^(2))xx 50=200` watt
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