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A particle of mass m and charge q moves ...

A particle of mass `m` and charge `q` moves with a constant velocity `v` along the positive `x` direction. It enters a region containing a uniform magnetic field `B` directed along the negative `z` direction, extending from `x = a` to `x = b`. The minimum value of `v` required so that the particle can just enter the region `x gt b` is

A

`(qbB)/(m)`

B

`(q(b-a)B)/(m)`

C

`(qaB)/(m)`

D

`(q(b+a)B)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
B

`R= (mv)/(qB) gt b-a`
`v= (qB(b-a))/(m)`
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