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A uniform circular disc placed on a hori...

A uniform circular disc placed on a horizontal rough surface has initially a velocity `v_(0)` and an angular velocity `omega_(0)` as shown in the figure. The disc comes to rest after moving some distance in the direction of motion. Then `v_(0)//omega_(0)` is `:`

A

`(1)/(2)`

B

2

C

`(1)/(3)`

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
From conservation of angular momentum about a point on the surface,
Initial angular momentum = final angular momentum:
`Mv_(0)r -(1)/(2) Mr^(2) omega_(0) =0`
Therefore `(v_(0))/(r omega_(0))=(1)/(2)`
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