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Power applied to a particle varies with time as `P =(3t^(2)-2t + 1)` watt, where t is in second. Find the change in its kinetic energy between time `t=2s` and `t = 4 s` .

Text Solution

Verified by Experts

The correct Answer is:
46

`P=3t^(2) -2t +1 =(dE)/(dt)`
`:.dE=(3t^(2)-2t +1)dt`
`E= int_(t=2s)^(t=4s) (3t^(2) -2t +1)dt`
`=[(3t^(3))/(3)-(2t^(2))/(2)+t]_(t=2s)^(t=4s)`
`=[(4^(3) -2^(3))-(4^(2)-2^(2)) +(4-2)]`
`E=56-12+2=46J`
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