A vessel of volume `5000 cm^3` contains `(1/20)` moles of molecular nitrogen at 1800K. If `30%` of the molecules are now dissociated the pressure inside the vessel (in Pa) will be

Options

A. `1.49 xx 10^(5)`
B. `1.94 xx 10^(5)`
C. `2.25 xx 10^(5)`
D. `3.78 xx 10^(5)`

Answer

B

Explanation

As 30% of the molecules are now dissociated then new number of moles are
`n = (1)/(20 )( 1.3 )`
And hence the new pressure is
PV = nRT
`P ( 5000 xx 10^(-6))`
`= (1)/(20) (1.3) (8.314 ) (1800)`
`P = 1.94 xx 10^(5) ` Pa