A block of mass 1 kg is connected with a smooth plank of the same mass is performing oscillations. The value of the spring constant is `200 N m^(-1)` The block and the plank are free to move and there is no friction anywhere. The angular frequency of the oscillation is `omega` rad `s^(-1)` Find the value of `omega`

Answer

20

Explanation

Using the concept of reduced mass, we obtain:
`omega= sqrt((k)/(m_("reduced ")))=sqrt((2k)/(m))`
`(becausem_("reduced")= (mxx m)/(m+m) = (m)/(2))`
`implies omega sqrt((2xx 200)/(1))= 20 "rad " s^(-1)`