The displacement time graph for two sound waves A and B are shown in the figure. Then the ratio of their intensities `I_(A)//I_(B)` is equal to

Options

A. `1:4`
B. `1:16`
C. `1:2`
D. `1:1`

Answer

D

Explanation

The intensity can be given by
`I=2pi^(2)rho^(2)A^(2)v`
Hence
`(I_(A))/(I_(B))=(f_(A)^(2)A_(A)^(2))/(f_(B)^(2)A_(B)^(2))`
`(I_(A))/(I_(B))=(1/2)^(2)(2/1)^(2)`
`(I_(A))/(I_(B))=1`