`1181+1520=(26)^2+(?)^2`

Options

A. 49
B. 43
C. 47
D. 45

Answer

To solve the equation \( 1181 + 1520 = (26)^2 + (?)^2 \), we will follow these steps:

### Step 1: Calculate \( 1181 + 1520 \)
First, we need to add the two numbers on the left side of the equation.

\[ 1181 + 1520 = 2701 \]

### Step 2: Calculate \( (26)^2 \)
Next, we need to calculate \( (26)^2 \).

\[ (26)^2 = 676 \]

### Step 3: Set up the equation
Now we can set up the equation using the results from Steps 1 and 2.

\[ 2701 = 676 + (?)^2 \]

### Step 4: Isolate \( (?)^2 \)
To find \( (?)^2 \), we need to isolate it on one side of the equation.

\[ (?)^2 = 2701 - 676 \]

### Step 5: Perform the subtraction
Now, we will perform the subtraction.

\[ (?)^2 = 2025 \]

### Step 6: Take the square root
To find \( ? \), we take the square root of both sides.

\[ ? = \sqrt{2025} \]

### Step 7: Calculate the square root
Now we will calculate the square root.

\[ ? = 45 \]

### Conclusion
Thus, the value of \( ? \) is \( 45 \).