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The factors of x^2+xy-2xz-2yzare...

The factors of `x^2+xy-2xz-2yz`are

A

(x-y)(x+2z)

B

(x+y)(x-2z)

C

(x-y)(x-2z)

D

(x+y)(x+2z)

Text Solution

AI Generated Solution

The correct Answer is:
To factor the expression \( x^2 + xy - 2xz - 2yz \), we can follow these steps: ### Step 1: Group the terms We can group the terms in pairs to make factoring easier: \[ (x^2 + xy) + (-2xz - 2yz) \] ### Step 2: Factor out common factors from each group In the first group \( (x^2 + xy) \), we can factor out \( x \): \[ x(x + y) \] In the second group \( (-2xz - 2yz) \), we can factor out \( -2z \): \[ -2z(x + y) \] ### Step 3: Combine the factored groups Now we can combine the two factored groups: \[ x(x + y) - 2z(x + y) \] ### Step 4: Factor out the common binomial factor Notice that \( (x + y) \) is a common factor: \[ (x + y)(x - 2z) \] ### Final Answer Thus, the factors of the expression \( x^2 + xy - 2xz - 2yz \) are: \[ (x + y)(x - 2z) \] ---
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