ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB.
Prove that ar (ABCD)= `ABxxDG`

ABCD is parallelogram and ABEF is a rectangle and DG is perpendicular on AB. Prove that (i) ar (ABCD) = ar(ABEF) (ii) ar (ABCD) = AB xx DG

ABCD is a cyclic parallelogram and AC = 9 cm, find BD.

ABCD is a parallelogram. AE is perpendicular on DC and cF is perpendicular on AD. If AB = 10 cm, AE = 8 cm and CF = 12 cm. Find AD

ABCD is a parallelogram. The diagonals AC and BD intersect each other at ‘O’. Prove that ar(DeltaAOD) = ar(DeltaBOC) . (Hint: Congruent figures have equal area)

ABCD is a parallelogram DE _|_ AB, DF_|_BC . Find DF.

ABCD is a parallelogram if angleBAD=110^@ then angleDCE =

ABCD is a parallelogram and angleA = 60^(@) . Find the remaining angles.

ABCD is a parallelogram then /_A-/_C = ……………degrees.