Home
Class 9
MATHS
Prove that the area of a trapezium is ha...

Prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them.

Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Area of a trapezium is 480 cm^2 . Length of one of the parallel sides is 24 cm and the distance between the parallel sides is 8 cm. Find the length of the other parallel side.

Prove that the area of a rhombus is equal to half of the product of the diagonals.

Area of a trapezium is 16 cm^(2) Length of one parallel side is 5 cm and distance between two parallel sides is 4 cm. Find the length of the other parallel side?

Area of a trapezium is 16 cm^2 . Length of one parallel side is 5 cm and distance between two parallel sides is 4 cm. Find the length of the other parallel side. Try to draw this trapezium on a graph paper and check the area.

Show that the following equations represents a pair of parallel lines and also find the distance between them. Show that the equation 8x^(2)-24xy+18y^(2)-6x+9y-5=0 represents a pair of parallel lines and find the distance between them.

The ratio of the length of the parallel sides of a trapezium is 5: 3 and the distance between them is 16 cm. If the area of the trapezium is 960 cm^2 , find the length of the parallel sides.

The ratio of the lengths of the parallel sides of a trapeziuin is 4:1. The distance between them is 10 cim. If the area of the trapezium is 500 cm^2 . Find the lengths of the parallel sides.

The sum of the hypotenuse and a side of a triangle are given. If the area of the triangle is maximum then the angle between them is

If the lines 2x+2y+3=0 and x+y+1=0 are parallel then the distance between them is