ABC is an isoscles triangle with `bar(AB)= bar(AC) and bar(AD)` is one of its altitudes. Is `DeltaADB ~= DeltaADC` ? Why or why not?

ABC is an isoscles triangle with bar(AB)= bar(AC) and bar(AD) is one of its altitudes. Is BD = CD ? Why or why not?

ABC is an isosceles triangle with bar(AB)= bar(AC) and bar(AD) is one of its altitudes (fig..). Is triangleABD ~= triangleACD ? Why or why not?

ABC is an isoscles triangle with bar(AB)= bar(AC) and bar(AD) is one of its altitudes (fig..). State the three pairs of equal parts in DeltaADB and DeltaADC .

In the adjacent figure, bar(BD) and bar(CE) are altitudes of DeltaABC such that BD= CE. Is DeltaCBD ~= DeltaBCE ? Why or why not?

In the adjacent figure DeltaABC and DeltaDBC are two triangles such that bar(AB) = bar(BD) and bar(AC) = bar(CD) . Show that DeltaABC ~= DeltaDBC.

In the parallelogram if bar(AB)=bar(a) and bar(AD)=bar(d) then find bar(BD) .

If ABCD is a parallelogram then bar(AC)+bar(BD)=

In the adjacent figure, bar(DA) bot bar(AB), bar(CB)bot bar(AB) and AC=BD . Prove that Delta ABC ~= DeltaBAD

In the adjacent figure triangle ABC is isosceles as bar (AB) =bar(AC), bar(BA) and bar(CA) are produced to Q and P such that bar(AQ)= bar(AP) .. Show that bar(PB) =bar(QC)