Find : `(kl + 2mn)^(2)`

Find: (6kl+ 7mn)²

Assertion (A) : The slopes of one line represented by 2x^(2)–5xy+2y^(2) = 0 is 4 times the slope of the second line. Reason (R): If the slopes of lines represented by ax^(2)+2hxy+by^(2)=0 are in m:n then ((m+n)^(2))/(mn)=(4h^(2))/(ab)

Simplify the following : (2m + n) (m^(3) - mn + n^(3))

Factorise the expressions - mn + m^(2) + mn^(2)

Find the product : (7m - kl + km)(5k - lm)

If the slopes of the lines represented by ax^(2)+2hxy+by^(2)=0 are in the ratio m:n then ((m+n)^(2))/(mn)=

Simplify the following : (m-n)(m^(2)+mn+n^(2))

In the reaction : C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) to Mn^(2+)+CO_(2)+H_(2)O , the oxidising agent is

Find the product: (2mn-kl+k)(kl+lm)

Select a suitable identity and find the following products:(kl-mn) (kl + mn)