Find x if 2 log 5 + `(1)/(2)` log 9 - log 3 = log x

Find x if 2log5+(1)/(2) log9-log3=logx.

2 log 3 + 3 log 5 - 5 log 2 = ........

f(x) - log (x^(2) + 2) - log 3 in [-1, 1]

If x^2 + y^2 = 10xy , prove that 2 log (x + y) = log x + log y + 2 log 2 + log 3 .

log ( 4x ^(2) - 9)

If x^(2) + y^(2)=6xy , prove that 2 log (x+ y)= log x + log y + 3 log 2

If x^2 + y^2 = 6xy , prove that 2 log (x + y) = logx + logy + 3 log 2

The derivative of (log x) ^(x) w.r.t x is (log x)^(x-1) [1+ log x log (log x)] R : (d)/(dx) {f (x) ^(g(x))[g (x) (f'(x))/(f (x)) + g'(x) log (f(x) ]

Note : log x = log_10 x : log 5^23

Find the derivative of the w.r.t.x log [(sin (log x ) + x log x log (log x)]