Can the number `6^n`, n being a natural number, end with the digit 5 ? Give reason.

Consider the number 4^n where n is a natural number. Check whether there is any value of n which 4^n ends with the digit zero?

Find the sum of : the first n natural numbers

Find the mean of first ‘n’ natural numbers.

If n is a natural number, then which of the following expression ends in zero?

The mean of first 'n' odd natural numbers is

The natural number 5 can be written as__

If the mean of first n natural numbers is 11 then n =

The simple and weighted arithmetic mean of the first n natural numbers, the weights being the corresponding numbers is

The A.M of first n natural numbers is

The number of natural numbers less than 1000, in which no two digits are repeated is