`DeltaABC~DeltaDEF` ,BC=3cm, EF=4cm and area of `DeltaABC`= 54`cm^2`. Determine the area of `DeltaABC`.

Find the area of DeltaABC.

Delta ABC ~ Delta DEF . BC = 4 cm and EF=6cm area of Delta ABC = 54 cm^(2) Determine the area of Delta DEF .

DeltaABC~DeltaDEF , BC=4cm, EF=5cm and area of DeltaABC=80cm^2 then area of DeltaDEF =………… cm^2

triangle ABC ~ triangle DEF , BC = 5 cm, EF = 6cm and area of triangle DEF = 72 cm^2 . Determine the area of triangle ABC

In DeltaABC , area of incircle : area of DeltaABC =

DeltaABC~DeltaDEF and areas of DeltaABC , DeltaDEF are 64cm^2 and 121cm^2 then the ratio of corresponding sides.

If G is the centroid of DeltaABC and if area of DeltaAGB is 5 sq.unit. then the area of DeltaABC is

If A , B , C are collinear then area of DeltaABC = .....

In a DeltaDEF , A, B and C are mid points of EF,FD and DE respectively. IF the area of DeltaDEF is 14.4 cm^2 then find the area of DeltaABC .

IF DeltaPQR~DeltaXYZ , QR=3cm , YZ=4cm DeltaPQR area =54 cm^2 . Then DeltaXYZ area=………….