ABD is a Triangle right angle at A and `AC bot BD`.
Show that (i) `AB^2=BC.BD`
(ii) `AD^2=BD.CD`
(iii) `AC^2=BC.DC`

ABD is a triangle right angled at A and ACbotBD . Show that i) AB^2=BC*BD

ABD is a triangle right angled at A and ACbotBD .Showthat i) AB^2=BC*BD ii) AC^2=BC*DC iii) AD^2=BD*CD

ABDisatrianglerightangledatAand ACbotBD .Showthat ii) AC^2=BC*DC

In triangle ACB , angle C = 90^@ and CD bot AB . Prove that BC^2/AC^2 = BD/AD .

In the given figure, ABC is a Triangle right angled at B.D and E are points on BC trisect it. Prove that 8AE^2=3AC^2+5AD^2 .

In triangle ABC right angle at B, AB=x,BC=y,AC=r then costheta =

In triangle ABC right angle at B, AB=x,BC=y,AC=r then tantheta =

In the given figure ABC is a right triangle and right angled at B such that /_BCA = 2/_BAC. Show that hypotenuse AC = 2BC.

ABC is a right Triangle right angled at B.Let D and E be any points on AB and BC respectively. Prove that AE^2+CD^2=AC^2+DE^2 .

ABCD is a quadrilateral in which AD = BC and /_ DAB = /_ CBA Prove that (i) DeltaABD ~= DeltaBAC (ii) BD = AC (iii) /_ ABD = /_ BAC