3.15 Grams of oxalic acid crystals are present in a 500 mL aqueous solution. Calculate (a) molarity and (b) normality.

Explanation

To solve the problem step by step, we will first calculate the molarity and then the normality of the oxalic acid solution.

### Step 1: Calculate the Molarity

**Formula for Molarity (M):**
\[ M = \frac{\text{Weight of solute (g)}}{\text{Molar mass of solute (g/mol)} \times \text{Volume of solution (L)}} \]

**Given:**
...