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50 mL of normal sulphuric acid neutralis...

50 mL of normal sulphuric acid neutralises 10 mL of potash solution. Calculate the strength of potash in mol `L^(-) and g L^(-1)`.

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To solve the problem step by step, we will use the information provided in the question and apply the principles of neutralization and normality. ### Step 1: Understand the given data - Volume of sulfuric acid (H₂SO₄) = 50 mL - Normality of sulfuric acid (H₂SO₄) = 1 N - Volume of potash solution (KOH) = 10 mL - Normality of KOH = ? ...
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