It is desired to prepare one litre of decimolar aqueous aluminium sulphate. Find the amount of solute to be weighed. Calculate the number of gram ions of sulphate in the solution.

Explanation

To solve the problem of preparing a decimolar (0.1 M) aqueous solution of aluminum sulfate (Al₂(SO₄)₃), we will follow these steps:

### Step 1: Determine the Molar Mass of Aluminum Sulfate
Aluminum sulfate has the formula Al₂(SO₄)₃. To calculate its molar mass, we need to sum the atomic masses of all the atoms in the formula:
- Aluminum (Al): 2 atoms × 27 g/mol = 54 g/mol
- Sulfate (SO₄): 3 groups × (32 g/mol for S + 4 × 16 g/mol for O) = 3 × (32 + 64) = 3 × 96 = 288 g/mol

Now, adding these together:
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