Vapour pressure of pure water at `27^@C` is 3000k Pa. By dissolving 5 g of a non volatile molecular solid in 100 g of water the vapour pressure is decreased to 2985 k Pa. What si the molecular weight of solute?

Explanation

To solve the problem of finding the molecular weight of the solute, we will use the concept of vapor pressure lowering, which is governed by Raoult's law. Here’s a step-by-step solution:

### Step 1: Identify the given values
- Vapor pressure of pure water (P₀) = 3000 kPa
- Vapor pressure of the solution (P) = 2985 kPa
- Mass of the solute (non-volatile molecular solid) = 5 g
- Mass of the solvent (water) = 100 g

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