At `10^@C`, the osmotic pressure of 1% (w/v) solution of 'X' is `7.87 xx 10^(4) Nm^(-2)`. What is the molecular weight of solute X ?

Explanation

To find the molecular weight of the solute 'X' from the given data, we can use the formula for osmotic pressure:

\[ \pi = \frac{w}{M_w} \cdot \frac{RT}{V} \]

Where:
- \(\pi\) = osmotic pressure (in Pascals)
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