7g of a solute are dissolved in 200 g of a solvent (mol. Wt. 78) to prepare a solution. At a certain temperature dry air is sent into a solution and solvent continuously. The loss is weights of containers containing solutions and solvent are 0.975 g and 0.025 g. Calculate the molar mass of solute.

Explanation

To solve the problem, we will use the concept of relative lowering of vapor pressure (RLVP) and Raoult's law. Here's a step-by-step breakdown of the solution:

### Step 1: Understand the given data
- Mass of solute (W_solute) = 7 g
- Mass of solvent (W_solvent) = 200 g
- Molecular weight of solvent (M_solvent) = 78 g/mol
- Weight loss of solution (W_loss_solution) = 0.975 g
- Weight loss of solvent (W_loss_solvent) = 0.025 g
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