If extent of dissociation of both KCl and `BaCl_2` of some concentrations with identical value of `alpha` as 0.9, what is the ratio of their van't Hoff factors?

Explanation

To find the ratio of the van't Hoff factors (i) for KCl and BaCl₂ given their extent of dissociation (α) is 0.9, we can follow these steps:

### Step 1: Understand the van't Hoff factor (i)
The van't Hoff factor (i) is defined as the number of particles into which a solute dissociates in solution. For ionic compounds, this can be calculated using the formula:
\[ \alpha = \frac{i - 1}{n - 1} \]
where:
- \( \alpha \) = extent of dissociation
- \( i \) = van't Hoff factor
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