Home
Class 12
CHEMISTRY
Mass percentage (w/w) of ethylene glycol...

Mass percentage (w/w) of ethylene glycol. `(HOCH_2 - CH_2OH)` in an aqueous solution is 20. Calculate mole fraction of solute.

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the mole fraction of ethylene glycol in an aqueous solution where the mass percentage of ethylene glycol is 20%, we can follow these steps: ### Step 1: Understand the Mass Percentage The mass percentage of ethylene glycol (C2H6O2) in the solution is given as 20%. This means that in 100 grams of the solution, there are 20 grams of ethylene glycol and 80 grams of water. ### Step 2: Calculate the Number of Moles of Ethylene Glycol First, we need to calculate the molecular weight of ethylene glycol (C2H6O2): - Carbon (C): 12 g/mol × 2 = 24 g/mol - Hydrogen (H): 1 g/mol × 6 = 6 g/mol - Oxygen (O): 16 g/mol × 2 = 32 g/mol Adding these together: \[ \text{Molecular weight of ethylene glycol} = 24 + 6 + 32 = 62 \text{ g/mol} \] Now, we can calculate the number of moles of ethylene glycol: \[ n_1 = \frac{\text{mass of ethylene glycol}}{\text{molecular weight}} = \frac{20 \text{ g}}{62 \text{ g/mol}} \approx 0.323 \text{ moles} \] ### Step 3: Calculate the Number of Moles of Water Next, we calculate the number of moles of water (H2O): - The mass of water in the solution is 80 grams. - The molecular weight of water is: - Hydrogen (H): 1 g/mol × 2 = 2 g/mol - Oxygen (O): 16 g/mol × 1 = 16 g/mol \[ \text{Molecular weight of water} = 2 + 16 = 18 \text{ g/mol} \] Now, we can calculate the number of moles of water: \[ n_2 = \frac{\text{mass of water}}{\text{molecular weight}} = \frac{80 \text{ g}}{18 \text{ g/mol}} \approx 4.444 \text{ moles} \] ### Step 4: Calculate the Mole Fraction of Ethylene Glycol The mole fraction of a component is given by the formula: \[ \text{Mole fraction of solute (ethylene glycol)} = \frac{n_1}{n_1 + n_2} \] Substituting the values we calculated: \[ \text{Mole fraction of ethylene glycol} = \frac{0.323}{0.323 + 4.444} \approx \frac{0.323}{4.767} \approx 0.0677 \] ### Final Answer: The mole fraction of ethylene glycol in the solution is approximately **0.0677**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

3.2 molal aqueous solution will have mole fraction of solute equal to

The mole fraction of methyl alcohol in an aqueous solution is 0.02. Calculate the molality of the solution.

The mole fraction of solute in aqueous urea solution is 0.2. Calculate the mass percent of solute ?

Percent by mass of solute (molar mass = 25 g/mol) in its aqueous solution is 30. The mole fraction and molality of the solute in solution are

Mole fraction of a solute in an aqueous solution is 0.2. The molality of the solution will be

If the mass percentage of urea in an aqueous solution is 20% then molality of the solution will be

An antifreeze mixture consists of 40% ethylene glycol (C_(2)H_(6)O_(2)) by weight in aqueous solution. If the density of this solution is 1.05 g//"mol" , what is the molar concentration :

The vapour pressure of an aqueous solution of glucose is 750 mm of Hg at 373 K . Calculate molality and mole fraction of solute.

Calculate the normally of 10.6 % (w/v) Na_2CO_3 in aqueous solutions.

Mole fraction of solute in aqueous solution of 30% NaOH.