Length of a face edge in lithium chloride crystal is `5.11 A^(0) `. What is the radius of anion of the crystal?

Explanation

To find the radius of the anion in a lithium chloride (LiCl) crystal, we can use the relationship between the edge length of the face-centered cubic (FCC) lattice and the radius of the ions. Here’s a step-by-step solution:

### Step 1: Understand the FCC Structure
In a face-centered cubic (FCC) lattice, the ions are arranged in such a way that each corner of the cube and the centers of each face have ions. In the case of LiCl, we can consider Li⁺ as the cation and Cl⁻ as the anion.

### Step 2: Use the Relationship Between Edge Length and Radius
For an FCC lattice, the relationship between the edge length (a) and the radius (r) of the ions is given by the formula:
\[ r = \frac{a}{2\sqrt{2}} \]
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