The non - stoichiometric iron oxide has a composition `Fe_(0.94) O`. Find the ratio of ferrous and ferric ions present in it.

Explanation

To solve the problem of finding the ratio of ferrous (Fe²⁺) and ferric (Fe³⁺) ions in the non-stoichiometric iron oxide with the composition Fe₀.₉₄O, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Composition**:
The given composition of the iron oxide is Fe₀.₉₄O. This indicates that there are 0.94 moles of iron (Fe) for every mole of oxygen (O).

2. **Set Up the Ion Composition**:
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