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For a cubic lattice edge length of unit ...

For a cubic lattice edge length of unit cell is `5A^(0)` and density is `2gcc^(-1)`. Calculate the radius of an atom, if gram atomic weight is 75 g `mol^(-1)`.

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To solve the problem, we need to calculate the radius of an atom in a cubic lattice given the edge length of the unit cell, the density, and the gram atomic weight. Here’s a step-by-step solution: ### Step 1: Understand the given data - Edge length of the unit cell (a) = 5 Å (angstroms) - Density (d) = 2 g/cm³ - Gram atomic weight (M) = 75 g/mol ### Step 2: Convert the edge length to cm ...
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Knowledge Check

  • Chromium metal crystallizes with a body-centred cubic lattice. The length of the unit cell edge is found to be 287 pm. Calculate the atomic radius. What woulds be the density of chromium in g cm^(-3) ?

    A
    124.27 pm
    B
    287 pm
    C
    574 pm
    D
    143.5 pm
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