Resistance of a conductivity cell filled with 0.1 mol `L^(-1)`KCl solution is `100Omega` . If the resistance of the same cell when filled with 0.02 mol L ^(-1) KCl solution is `520Omega` . Calculate the conductivity and molar conductivity of `0.02 Mol L^(-1)`KCL solution . The conductivity of `0.1molL^(-1)` KCL Solution is `1.29xx10^(-2) Omega ^(-1) cm^(-1)`.

Explanation

The cell constant filled with electrolytic solution is given as,
Cell constant = specific conductivity `xx` resistance
Cell constant = `1.29 S m^(-1) xx 100 Omega`
`= 1.29 m^(-1) = 129 cm^(-1)`.