A matel wire carries a current of one amp. How many electrons pass a point in the wire in one sec.

Answer

To find out how many electrons pass a point in a metal wire carrying a current of 1 ampere in one second, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between current, charge, and time**:
- The formula for electric current (I) is given by:
\[ I = \frac{Q}{T} \]
where \(I\) is the current in amperes, \(Q\) is the charge in coulombs, and \(T\) is the time in seconds.

2. **Calculate the charge (Q)**:
- We are given that the current \(I = 1 \, \text{A}\) and the time \(T = 1 \, \text{s}\).
- Rearranging the formula gives us:
\[ Q = I \times T = 1 \, \text{A} \times 1 \, \text{s} = 1 \, \text{C} \]

3. **Determine the number of electrons in 1 coulomb**:
- We know that 1 coulomb of charge is equivalent to the charge of approximately \(6.022 \times 10^{23}\) electrons (this is Avogadro's number).
- The charge of one electron is approximately \(1.602 \times 10^{-19} \, \text{C}\).

4. **Calculate the number of electrons (n)**:
- To find the number of electrons that correspond to 1 coulomb, we can use the formula:
\[ n = \frac{Q}{e} \]
where \(e\) is the charge of one electron.
- Substituting the values, we have:
\[ n = \frac{1 \, \text{C}}{1.602 \times 10^{-19} \, \text{C/electron}} \approx 6.242 \times 10^{18} \, \text{electrons} \]

5. **Final Answer**:
- Therefore, the number of electrons passing a point in the wire in one second is approximately:
\[ n \approx 6.24 \times 10^{18} \, \text{electrons} \]